X^2+3=(x+4)(x-5)

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Solution for X^2+3=(x+4)(x-5) equation: 



X^2+3=(X+4)(X-5)

We move all terms to the left:

X^2+3-((X+4)(X-5))=0

We multiply parentheses ..

X^2-((+X^2-5X+4X-20))+3=0



We calculate terms in parentheses: -((+X^2-5X+4X-20)), so:

(+X^2-5X+4X-20)

We get rid of parentheses

X^2-5X+4X-20

We add all the numbers together, and all the variables

X^2-1X-20

Back to the equation:

-(X^2-1X-20)



We get rid of parentheses

X^2-X^2+1X+20+3=0

We add all the numbers together, and all the variables

X+23=0

We move all terms containing X to the left, all other terms to the right

X=-23

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